# Line slope calculator 5x-3y=12

**Straight line given by points A[3; 1] and B[6; 6]**

## Calculation:

**Slope-intercept form of line:**y = 1.6667x-4

**Canonical form of the line equation:**5x-3y-12 = 0

**Parametric form of the line equation:**

x = 3t+3

y = 5t+1 ; t ∈ R

**Slope:**m = 1.6667

**Slope angle of line: φ =**59°2'10″ = 1.0304 rad

**X intercept:**x

_{0}= 2.4

**Y intercept:**y

_{0}= q = -4

**Distance line from the origin:**d

_{0}= 2.058

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; 5)

**Normal vector: n =**(5; -3)

**Midpoint of the segment AB: M =**[4.5; 3.5]

**Perpendicular Bisector equation:**3x+5y-31 = 0

**Vector OA = (3; 1) ; |OA| = 3.1623**

**Vector OB = (6; 6) ; |OB| = 8.4853**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**